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IsBinarySumTree.cpp
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// { Driver Code Starts
#include <bits/stdc++.h>
using namespace std;
struct Node
{
int data;
struct Node *left;
struct Node *right;
};
// Utility function to create a new Tree Node
Node* newNode(int val)
{
Node* temp = new Node;
temp->data = val;
temp->left = NULL;
temp->right = NULL;
return temp;
}
// Function to Build Tree
Node* buildTree(string str)
{
// Corner Case
if(str.length() == 0 || str[0] == 'N')
return NULL;
// Creating vector of strings from input
// string after spliting by space
vector<string> ip;
istringstream iss(str);
for(string str; iss >> str; )
ip.push_back(str);
// Create the root of the tree
Node* root = newNode(stoi(ip[0]));
// Push the root to the queue
queue<Node*> queue;
queue.push(root);
// Starting from the second element
int i = 1;
while(!queue.empty() && i < ip.size()) {
// Get and remove the front of the queue
Node* currNode = queue.front();
queue.pop();
// Get the current node's value from the string
string currVal = ip[i];
// If the left child is not null
if(currVal != "N") {
// Create the left child for the current node
currNode->left = newNode(stoi(currVal));
// Push it to the queue
queue.push(currNode->left);
}
// For the right child
i++;
if(i >= ip.size())
break;
currVal = ip[i];
// If the right child is not null
if(currVal != "N") {
// Create the right child for the current node
currNode->right = newNode(stoi(currVal));
// Push it to the queue
queue.push(currNode->right);
}
i++;
}
return root;
}
// Should return true if tree is Sum Tree, else false
class Solution {
public:
int sumTree(Node* root, bool& flag) {
if (!root) return 0;
int oldValue = root->data;
int height = sumTree(root->left, flag) + sumTree(root->right, flag);
if((root->left || root->right) && height != root->data) {
flag = false;
return height + oldValue;
}
return height + oldValue;
}
bool isSumTree(Node* root) {
bool flag = true;
if (!root) return flag;
sumTree(root, flag);
return flag;
}
};
int main()
{
int t;
scanf("%d ",&t);
while(t--)
{
string s;
getline(cin,s);
Node* root = buildTree(s);
Solution ob;
cout <<ob.isSumTree(root) << endl;
}
return 1;
}