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Problem92.js
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// Problem 92
//
// This problem was asked by Airbnb.
//
// We're given a hashmap associating each courseId key with a list of courseIds values, which represents that the prerequisites of courseId are courseIds. Return a sorted ordering of courses such that we can finish all courses.
//
// Return null if there is no such ordering.
//
// For example, given {'CSC300': ['CSC100', 'CSC200'], 'CSC200': ['CSC100'], 'CSC100': []}, should return ['CSC100', 'CSC200', 'CSC300'].
//
// https://leetcode.com/problems/course-schedule-ii/
/**
* Returns a sorted ordering of courses such that we can finish all courses
* @param {Map<string, Set<string>>} courses
* @return {string[]}
*/
function courseOrder(courses) {
// get all courses with no dependencies and put onto queue
const courseQueue = [];
const ordering = [];
const coursesKeys = Array.from(courses.keys());
for (let i = 0; i < coursesKeys.length; i++) {
const courseName = coursesKeys[i];
if (courses.get(courseName).size === 0) {
courseQueue.push(courseName);
}
}
// dequeue course from queue and add to the ordering, then delete that course from any of the courses that may depend on it.
// When deleting the course, if that course has no more dependencies, add onto the queue.
while (courseQueue.length !== 0) {
const course = courseQueue.shift();
ordering.push(course);
for (let i = 0; i < coursesKeys.length; i++) {
const courseName = coursesKeys[i];
if (course !== courseName) {
const courseDependencies = courses.get(courseName);
if (courseDependencies.has(course)) {
courseDependencies.delete(course);
if (courseDependencies.size === 0) courseQueue.push(courseName);
}
}
}
}
// check if there are any dependencies left for all the courses. If there is, it is a cyclic graph, so there is no such ordering.
for (let i = 0; i < coursesKeys.length; i++) {
const courseName = coursesKeys[i];
if (courses.get(courseName).size !== 0) return [];
}
// no more dependencies left, means the ordering is correct
return ordering;
}
export default courseOrder;