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74.search-a-2-d-matrix.java
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/*
* @lc app=leetcode id=74 lang=java
*
* [74] Search a 2D Matrix
*
* https://leetcode.com/problems/search-a-2d-matrix/description/
*
* algorithms
* Medium (35.15%)
* Likes: 975
* Dislikes: 116
* Total Accepted: 243.3K
* Total Submissions: 692.3K
* Testcase Example: '[[1,3,5,7],[10,11,16,20],[23,30,34,50]]\n3'
*
* Write an efficient algorithm that searches for a value in an m x n matrix.
* This matrix has the following properties:
*
*
* Integers in each row are sorted from left to right.
* The first integer of each row is greater than the last integer of the
* previous row.
*
*
* Example 1:
*
*
* Input:
* matrix = [
* [1, 3, 5, 7],
* [10, 11, 16, 20],
* [23, 30, 34, 50]
* ]
* target = 3
* Output: true
*
*
* Example 2:
*
*
* Input:
* matrix = [
* [1, 3, 5, 7],
* [10, 11, 16, 20],
* [23, 30, 34, 50]
* ]
* target = 13
* Output: false
*
*/
class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
if (matrix == null || matrix.length == 0 || matrix[0].length == 0) {
return false;
}
int row = searchLastLess(matrix, target);
if (row == -1) {
return false;
}
return search(matrix, row, target);
}
public boolean search(int[][] matrix, int row, int target) {
int low = 0;
int high = matrix[row].length - 1;
while (low <= high) {
int mid = low + (high - low) / 2;
if (matrix[row][mid] == target) {
return true;
} else if (matrix[row][mid] < target) {
low = mid + 1;
} else {
high = mid - 1;
}
}
return false;
}
public int searchLastLess(int[][] matrix, int target) {
int low = 0;
int high = matrix.length - 1;
while (low <= high) {
int mid = low + (high - low) / 2;
if (matrix[mid][0] > target) {
high = mid - 1;
} else {
if (mid == matrix.length - 1 || matrix[mid + 1][0] > target) {
return mid;
} else {
low = mid + 1;
}
}
}
return -1;
}
}