Add/update source block delimeters (#83624) (#83854)

Asciidoc source blocks are to be delimited with four dashes. This adds missing delimiters, and updates some that contained only three dashes. It matters for parsing purposes.

(cherry picked from commit 5ef77ef)

Co-authored-by: edh-oss <[email protected]>

Author: jrodewig

docs/reference/how-to/fix-common-cluster-issues.asciidoc

@@ -693,9 +693,9 @@ see the number of active threads in each thread pool and
 how many tasks are queued, how many have been rejected, and how many have completed. 
 
 [source,console]
----
+----
 GET /_cat/thread_pool?v&s=t,n&h=type,name,node_name,active,queue,rejected,completed
----
+----
 
 **Inspect the hot threads on each node**
 
@@ -705,9 +705,9 @@ to determine if the thread has sufficient
 resources to progress and gauge how quickly it is progressing.
 
 [source,console]
----
+----
 GET /_nodes/hot_threads
----
+----
 
 **Look for long running tasks**
 

docs/reference/sql/functions/conditional.asciidoc

@@ -86,10 +86,12 @@ E.g.:
 for the following query:
 
 [source, sql]
+----
 CASE WHEN a = 1 THEN null
      WHEN a > 2 THEN 10
      WHEN a > 5 THEN 'foo'
 END
+----
 
 an error message would be returned, mentioning that *'foo'* is of data type *keyword*,
 which does not match the expected data type *integer* (based on result *10*).
@@ -105,6 +107,7 @@ interesting than every single value, CASE can create custom buckets as in the
 following example:
 
 [source, sql]
+----
 SELECT count(*) AS count,
   CASE WHEN NVL(languages, 0) = 0 THEN 'zero'
     WHEN languages = 1 THEN 'one'
@@ -115,7 +118,7 @@ SELECT count(*) AS count,
 FROM employees
 GROUP BY lang_skills
 ORDER BY lang_skills;
-
+----
 With this query, one can create normal grouping buckets for values _0, 1, 2, 3_ with
 descriptive names, and every value _>= 4_ falls into the _multilingual_ bucket.
 
@@ -281,7 +284,9 @@ include-tagged::{sql-specs}/docs/docs.csv-spec[iifWithoutDefaultValue]
 expression. E.g.:
 
 [source, sql]
+----
 IIF(a = 1, 'one', IIF(a = 2, 'two', IIF(a = 3, 'three', 'many')))
+----
 =================