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pvsystem.py - no continuous IV curve data #83
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Thanks, Birk. I'm not sure how to best construct the API for this. I removed the Also, I think that What do others think? |
Here's my code to make IV curves. I'm still not sure if any of this should be included in pvlib or not. I think we should at least add something similar to this to the documentation. Maybe someone else has a better way to do this. def fivepoints_to_frame(pnt):
"""
Converts a 1 dimensional, dict-like singlediode or sapm result
to a 5 row DataFrame with columns current and voltage.
Users can iterate over the rows of a multidimensional
singlediode or sapm result, if necessary.
"""
ivframe = {'i_sc': (pnt['i_sc'], 0),
'p_mp': (pnt['i_mp'], pnt['v_mp']),
'i_x': (pnt['i_x'], 0.5*pnt['v_oc']),
'i_xx': (pnt['i_xx'], 0.5*(pnt['v_oc']+pnt['v_mp'])),
'v_oc': (0, pnt['v_oc'])}
ivframe = pd.DataFrame(ivframe, index=['current', 'voltage']).T
ivframe = ivframe.sort_values(by='voltage')
return ivframe
resistance_shunt = 16
resistance_series = 0.094
nNsVth = 0.473
saturation_current = 1.943e-09
photocurrent = 7
module_parameters = pvsystem.retrieve_sam('cecmod')['Example_Module']
v_oc = pvsystem.v_from_i(resistance_shunt, resistance_series, nNsVth, 0, saturation_current, photocurrent)
voltage = np.linspace(0, v_oc, 100)
current = pvsystem.i_from_v(resistance_shunt, resistance_series, nNsVth, voltage, saturation_current, photocurrent)
fivepnts = pvsystem.singlediode(
module_parameters, photocurrent, saturation_current, resistance_series, resistance_shunt, nNsVth)
ivframe = fivepoints_to_frame(fivepnts)
fig, ax = plt.subplots()
ax.plot(voltage, current)
ax.scatter(ivframe['voltage'], ivframe['current'], c='k', s=36, zorder=10)
ax.set_xlim(0, None)
ax.set_ylim(0, None)
ax.set_ylabel('current (A)')
ax.set_xlabel('voltage (V)') The fivepnts
{'i_mp': 6.104597093609919,
'i_sc': 6.9584938427061607,
'i_x': 6.6367680322891767,
'i_xx': 4.4589886731292712,
'p_mp': 51.257040864030472,
'v_mp': 8.3964658237125214,
'v_oc': 10.362416515927016} and creates this output print(ivframe)
current voltage
i_sc 6.958494 0.000000
i_x 6.636768 5.181208
p_mp 6.104597 8.396466
i_xx 4.458989 9.379441
v_oc 0.000000 10.362417 requires #190. |
Will, I’d include the code, but I’d also have the function return a second dataframe with all 100 computed points. Cliff |
Another option is to reproduce the pvl_singlediode.m Matlab API by switching our singlediode's output from a DataFrame a simple dictionary. The dictionary values would be scalars or arrays as determined by the numpy broadcasting rules. Here's another try at the multiple function approach. We'd have the existing I don't know if one approach is better than the other. def singlediode_points_to_frame(pnt):
"""
Converts a dict of scalars describing the 5 points of
a single diode curve to a 5 row DataFrame with
columns current and voltage.
Useful for plotting.
Parameters
----------
pnt: dict
Typically the output of the singlediode function.
Must have keys i_sc, p_mp, i_x, i_xx, v_oc.
Returns
-------
fivepnts: DataFrame
Columns labeled voltage, current.
Rows labeled i_sc, p_mp, i_x, i_xx, v_oc.
"""
fivepnts = {'i_sc': (pnt['i_sc'], 0),
'p_mp': (pnt['i_mp'], pnt['v_mp']),
'i_x': (pnt['i_x'], 0.5*pnt['v_oc']),
'i_xx': (pnt['i_xx'], 0.5*(pnt['v_oc']+pnt['v_mp'])),
'v_oc': (0, pnt['v_oc'])}
fivepnts = pd.DataFrame(fivepnts, index=['current', 'voltage']).T
fivepnts = fivepnts.sort_values(by='voltage')
return fivepnts
def singlediode_ivcurve(module_parameters, photocurrent, saturation_current,
resistance_series, resistance_shunt, nNsVth, v_oc=None, num=50):
"""
Creates a single diode IV curve with uniformly spaced points.
Parameters
----------
See singlediode
v_oc: None or float
Will be calculated if None.
num: int
Number of IV curve samples.
Returns
-------
ivcurve: DataFrame
Columns labeled voltage, current.
Rows labeled by point number.
"""
if v_oc is None:
v_oc = pvsystem.v_from_i(
resistance_shunt, resistance_series, nNsVth, 0, saturation_current, photocurrent)
voltage = np.linspace(0, v_oc, num)
current = pvsystem.i_from_v(
resistance_shunt, resistance_series, nNsVth, voltage, saturation_current, photocurrent)
ivcurve = pd.DataFrame(np.array([voltage, current]).T, columns=['voltage', 'current'])
return ivcurve
def singlediode_points_ivcurve(module_parameters, photocurrent, saturation_current,
resistance_series, resistance_shunt, nNsVth,
num=50):
"""
Solves the single diode model for scalar inputs and returns an IV curve
and the 5 IV curve characterization points.
Parameters
----------
see singlediode
Returns
-------
fivepnts: DataFrame
Columns labeled voltage, current.
Rows labeled i_sc, p_mp, i_x, i_xx, v_oc.
ivcurve: DataFrame
Columns labeled voltage, current.
Rows labeled by point number.
"""
fivepnts = pvsystem.singlediode(
module_parameters, photocurrent, saturation_current, resistance_series, resistance_shunt, nNsVth)
fivepnts = singlediode_points_to_frame(fivepnts)
ivcurve = singlediode_ivcurve(
module_parameters, photocurrent, saturation_current, resistance_series, resistance_shunt, nNsVth,
v_oc=fivepnts.ix['v_oc', 'voltage'])
return fivepnts, ivcurve
resistance_shunt = 16
resistance_series = 0.094
nNsVth = 0.473
saturation_current = 1.943e-09
photocurrent = 7
fivepnts, ivcurve = singlediode_points_ivcurve(
module_parameters, photocurrent, saturation_current, resistance_series, resistance_shunt, nNsVth)
fig, ax = plt.subplots()
ax.plot(ivcurve['voltage'], ivcurve['current'])
ax.scatter(fivepnts['voltage'], fivepnts['current'], c='k', s=36, zorder=10)
ax.set_xlim(0, None)
ax.set_ylim(0, None)
ax.set_ylabel('current (A)')
ax.set_xlabel('voltage (V)')
# as shown above |
I would prefer the dict output rather than the dataframe for IV curves. We won’t use the pandas time series functionality for IV curves so the extra overhead doesn’t make sense to me. |
People do use the singlediode function for time series analysis, though, so I don't want to take that away from them (or at least me). I think everyone can be happy, and very little code should break, if I amend my previous comment to say: The dictionary values would be scalars, arrays, or series as determined by the input type. See below for a couple of API proposals. Option 1 can be implemented immediately. Option 2 would break existing code. Option 3 (not shown), would use option 1 and create a separate "tuplizer" function. The tuples are nice for plotting. def singlediode(module, photocurrent, saturation_current,
resistance_series, resistance_shunt, nNsVth,
ivcurve_pnts=None):
"""
Parameters
----------
...
ivcurve_pnts: None or int
The number of points with which to simulate an IV curve.
If None or 0, an IV curve will not be generated.
Returns option 1
-------
output: dict
A dict with the following keys:
* i_sc - short circuit current in amperes.
* v_oc - open circuit voltage in volts.
* i_mp - current at maximum power point in amperes.
* v_mp - voltage at maximum power point in volts.
* p_mp - power at maximum power point in watts.
* i_x - current, in amperes, at ``v = 0.5*v_oc``.
* i_xx - current, in amperes, at ``V = 0.5*(v_oc+v_mp)``.
* i - None or iv curve current. I'd also consider an empty array or missing key instead of None.
* v - None or iv curve voltage. I'd also consider an empty array or missing key instead of None.
Returns option 2
-------
output: dict
A dict with the following keys and (voltage, current, power) values:
* i_sc - (0, i_sc, 0)
* v_oc - (v_oc, 0, 0)
* p_mp - (v_mp, i_mp, p_mp)
* i_x - (v_x, i_x, p_x) at ``v_x = 0.5*v_oc``
* i_xx - (v_xx, i_xx, p_xx) at ``v_xx = 0.5*(v_oc+v_mp)``
* ivcurve - None or (voltage, current, power) tuple. I'd also consider a tuple of empty arrays or a missing key instead of None.
""" |
What I meant, and perhaps didn’t say clearly, is that a dataframe (time series object) doesn’t seem a natural fit to contain a single IV curve. A time series of a point on IV curves (e.g., Isc) makes a lot of sense. Option 1 is better than 2, I think. |
The singlediode function, located in pvsystem.py, does not have the capability to return continuous current and voltage values. I have modified the code to include a loop:
si = np.ones((NumPoints,1))
sv = np.linspace(-1,1,NumPoints)
if NumPoints >= 2:
for i in range(NumPoints):
V[i,:] = Voc.values * sv[i]
I[i,:] = I_from_V(Rsh=Rsh, Rs=Rs, nNsVth=nNsVth, V=V[i,:], I0=I0, IL=IL)
This may not be the most efficient way but it worked.
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