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| 1 | +#include <stdio.h> |
| 2 | +#include <stdlib.h> |
| 3 | +struct Node // this is tree node |
| 4 | +{ |
| 5 | + struct Node* lchild; // lefe child as node in tree |
| 6 | + int data; // data element |
| 7 | + struct Node* rchild; // right child as node in tree |
| 8 | +}; |
| 9 | +// we are implementing tree with the help of queue |
| 10 | +struct Queue |
| 11 | +{ |
| 12 | + int size; // size of queue |
| 13 | + int front; // front of queue // using for del |
| 14 | + int rear; // last of queue used for insertion |
| 15 | + struct Node** Q; // this should be an aray of nodes |
| 16 | +}; |
| 17 | +void create(struct Queue* q, int size) // creating a queue // passing pointer and the size of queue |
| 18 | +{ |
| 19 | + q->size = size; // size of queue |
| 20 | + q->front = 0; // make front and rear as null intially |
| 21 | + q->rear = 0; |
| 22 | + q->Q = (struct Node**)malloc(q->size * sizeof(struct Node*)); // allocating space in heap |
| 23 | +} |
| 24 | +void enqueue(struct Queue* q, struct Node* x) // passing queue as pointer |
| 25 | +{ |
| 26 | + if ((q->rear + 1) % q->size == q->front) // checking wheather queue is full |
| 27 | + printf("Queue if FULL"); |
| 28 | + else |
| 29 | + { |
| 30 | + q->rear = (q->rear + 1) % q->size; |
| 31 | + q->Q[q->rear] = x; // push the data |
| 32 | + } |
| 33 | +} |
| 34 | +struct Node* dequeue(struct Queue* q) |
| 35 | +{ |
| 36 | + struct Node* x = NULL; |
| 37 | + if (q->front == q->rear) |
| 38 | + return NULL; |
| 39 | + else |
| 40 | + { |
| 41 | + q->front = (q->front + 1) % q->size; |
| 42 | + x = q->Q[q->front]; |
| 43 | + return x; |
| 44 | + } |
| 45 | +} |
| 46 | +int isEmpty(struct Queue q) |
| 47 | +{ |
| 48 | + return q.front == q.rear; |
| 49 | +} |
| 50 | +struct Node* root = NULL; |
| 51 | +void TreeCreate() |
| 52 | +{ |
| 53 | + struct Node* t, * p; |
| 54 | + int x;// val of root |
| 55 | + struct Queue q; |
| 56 | + create(&q, 20); // size of a queue should be bigger |
| 57 | + root = (struct Node*)malloc(sizeof(struct Node)); |
| 58 | + printf("Enter a Root Value :\n"); |
| 59 | + scanf_s("%d", &x); |
| 60 | + root->data = x; |
| 61 | + root->lchild = NULL; |
| 62 | + root->rchild = NULL; |
| 63 | + enqueue(&q, root); |
| 64 | + while (!isEmpty(q)) |
| 65 | + { |
| 66 | + p = dequeue(&q); |
| 67 | + printf("Enter Left Child of %d :", p->data); |
| 68 | + scanf_s("%d", &x); |
| 69 | + if (x != -1) |
| 70 | + |
| 71 | + { |
| 72 | + t = (struct Node*)malloc(sizeof(struct Node)); |
| 73 | + t->data = x; |
| 74 | + t->lchild = t->rchild = NULL; |
| 75 | + p->lchild = t; |
| 76 | + enqueue(&q, t); |
| 77 | + } |
| 78 | + printf("Enter Right Child of %d:", p->data); |
| 79 | + scanf_s("%d", &x); |
| 80 | + if (x != -1) |
| 81 | + { |
| 82 | + t = (struct Node*)malloc(sizeof(struct Node)); |
| 83 | + t->data = x; |
| 84 | + t->lchild = t->rchild = NULL; |
| 85 | + p->rchild = t; |
| 86 | + enqueue(&q, t); |
| 87 | + } |
| 88 | + } |
| 89 | + |
| 90 | +} |
| 91 | +int leafcount(struct Node * root) |
| 92 | +{ |
| 93 | + int x, y; |
| 94 | + if (root != NULL) |
| 95 | + { |
| 96 | + x = leafcount(root->lchild); |
| 97 | + y = leafcount(root->rchild); |
| 98 | + if (root->lchild == NULL && root->rchild == NULL) // condition for leaf node |
| 99 | + return x + y + 1; |
| 100 | + else |
| 101 | + return x + y; |
| 102 | + } |
| 103 | + return 0; |
| 104 | +} |
| 105 | +int deg2count(struct Node* root) |
| 106 | +{ |
| 107 | + int x, y; |
| 108 | + if (root != NULL) |
| 109 | + { |
| 110 | + x = deg2count(root->lchild); |
| 111 | + y = deg2count(root->rchild); |
| 112 | + if (root->lchild != NULL && root->rchild != NULL) // condition for node with deg 1 |
| 113 | + return x + y + 1; |
| 114 | + else |
| 115 | + return x + y; |
| 116 | + } |
| 117 | + return 0; |
| 118 | +} |
| 119 | +int deg_1_2count(struct Node* root) |
| 120 | +{ |
| 121 | + int x, y; |
| 122 | + if (root != NULL) |
| 123 | + { |
| 124 | + x = deg_1_2count(root->lchild); |
| 125 | + y = deg_1_2count(root->rchild); |
| 126 | + if (root->lchild != NULL || root->rchild != NULL) // condition for node having deg 1 as well as 2 |
| 127 | + return x + y + 1; |
| 128 | + else |
| 129 | + return x + y; |
| 130 | + } |
| 131 | + return 0; |
| 132 | +} |
| 133 | +int deg1count(struct Node* root) |
| 134 | +{ |
| 135 | + int x, y; |
| 136 | + if (root != NULL) |
| 137 | + { |
| 138 | + x = deg1count(root->lchild); |
| 139 | + y = deg1count(root->rchild); |
| 140 | + if (root->lchild != NULL ^ root->rchild != NULL) // condition for node having deg 1 |
| 141 | + return x + y + 1; |
| 142 | + else |
| 143 | + return x + y; |
| 144 | + } |
| 145 | + return 0; |
| 146 | +} |
| 147 | + |
| 148 | +int main() |
| 149 | +{ |
| 150 | + TreeCreate(); |
| 151 | + printf("total no of leaf node is %d \n",leafcount(root)); |
| 152 | + printf("total no of node with deg 2 is %d \n", deg2count(root)); |
| 153 | + printf("total no of node with deg 2 as well as 1 is %d \n", deg_1_2count(root)); |
| 154 | + printf("total no of node with deg 1 is %d \n", deg1count(root)); |
| 155 | + |
| 156 | +} |
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