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| 1 | +//https://leetcode.com/problems/maximal-rectangle/ |
| 2 | +class Solution { |
| 3 | +public: |
| 4 | +int largestRectangleArea(vector<int>& heights) { |
| 5 | + int n= heights.size(); |
| 6 | + vector<int> left,right; |
| 7 | + stack<pair<int,int>> s1,s2; |
| 8 | + int pseudo_index =-1; |
| 9 | + int pseudo_index1 =n; |
| 10 | + for (int i=0;i<n;i++) |
| 11 | + { |
| 12 | + if (s1.size()==0) |
| 13 | + { |
| 14 | + left.push_back(pseudo_index); |
| 15 | + } |
| 16 | + else if (s1.size()>0 && s1.top().first<heights[i]) |
| 17 | + { |
| 18 | + left.push_back(s1.top().second); |
| 19 | + } |
| 20 | + else if (s1.size()>0 && s1.top().first>=heights[i]) |
| 21 | + { |
| 22 | + while(s1.size()>0 && s1.top().first>=heights[i]) |
| 23 | + { |
| 24 | + s1.pop(); |
| 25 | + } |
| 26 | + if (s1.size()==0) |
| 27 | + { |
| 28 | + left.push_back(pseudo_index); |
| 29 | + } |
| 30 | + else |
| 31 | + { |
| 32 | + left.push_back(s1.top().second); |
| 33 | + } |
| 34 | + } |
| 35 | + s1.push({heights[i],i}); |
| 36 | + } |
| 37 | + for (int i=n-1;i>=0;i--) |
| 38 | + { |
| 39 | + if (s2.size()==0) |
| 40 | + { |
| 41 | + right.push_back(pseudo_index1); |
| 42 | + } |
| 43 | + else if (s2.size()>0 && s2.top().first<heights[i]) |
| 44 | + { |
| 45 | + right.push_back(s2.top().second); |
| 46 | + } |
| 47 | + else if (s2.size()>0 && s2.top().first >= heights[i]) |
| 48 | + { |
| 49 | + while(s2.size()>0 && s2.top().first >= heights[i]) |
| 50 | + { |
| 51 | + s2.pop(); |
| 52 | + } |
| 53 | + if (s2.size()==0) |
| 54 | + { |
| 55 | + right.push_back(pseudo_index1); |
| 56 | + } |
| 57 | + else |
| 58 | + { |
| 59 | + right.push_back(s2.top().second); |
| 60 | + } |
| 61 | + } |
| 62 | + s2.push({heights[i],i}); |
| 63 | + } |
| 64 | + reverse(right.begin(),right.end()); |
| 65 | + int m=INT_MIN; |
| 66 | + for (long long i=0;i<n;i++) |
| 67 | + { |
| 68 | + m=max(m,(right[i]-left[i]-1)*heights[i]);// taking max after finding area |
| 69 | + } |
| 70 | + return m; |
| 71 | + } |
| 72 | + |
| 73 | + int maximalRectangle(vector<vector<char>>& matrix) { |
| 74 | + int m=matrix.size(); |
| 75 | + if(m==0) return 0; |
| 76 | + int n=matrix[0].size(), result=0; |
| 77 | + vector<int> histogram(n, 0); |
| 78 | + |
| 79 | + for(int i=0; i<m; i++){ |
| 80 | + for(int j=0; j<n; j++){ |
| 81 | + if(matrix[i][j]=='1') |
| 82 | + histogram[j]+=1; |
| 83 | + else |
| 84 | + histogram[j]=0; |
| 85 | + } |
| 86 | + |
| 87 | + result = max(result, largestRectangleArea(histogram)); |
| 88 | + cout<<result<<" "; |
| 89 | + } |
| 90 | + return result; |
| 91 | + } |
| 92 | +}; |
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