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added palindromeCheck (trekhleb#806)
* added readme * added readme * adding palindromeCheck * adjusted README Co-authored-by: Oleksii Trekhleb <[email protected]>
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README.md

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* `A` [Combination Sum](src/algorithms/sets/combination-sum) - find all combinations that form specific sum
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* **Strings**
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* `B` [Hamming Distance](src/algorithms/string/hamming-distance) - number of positions at which the symbols are different
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* `B` [Palindrome Check](src/algorithms/string/palindrome-check) - is the string the same in reverse
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* `A` [Levenshtein Distance](src/algorithms/string/levenshtein-distance) - minimum edit distance between two sequences
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* `A` [Knuth–Morris–Pratt Algorithm](src/algorithms/string/knuth-morris-pratt) (KMP Algorithm) - substring search (pattern matching)
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* `A` [Z Algorithm](src/algorithms/string/z-algorithm) - substring search (pattern matching)
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# Palindrome Check
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A Palindrome is a string that reads the same forwards and backwards.
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This means that the second half of the string is the reverse of the
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first half.
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## Examples
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The following are palindromes (thus would return TRUE):
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- "a"
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- "pop" -> p + o + p
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- "deed" -> de + ed
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- "kayak" -> ka + y + ak
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- "racecar" -> rac + e + car
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The following are NOT palindromes (thus would return FALSE):
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- "rad"
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- "dodo"
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- "polo"
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## References
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[GeeksforGeeks - Check if a number is Palindrome](https://www.geeksforgeeks.org/check-if-a-number-is-palindrome/)
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import palindromeCheck from '../palindromeCheck';
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describe('palindromeCheck', () => {
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it('should return whether or not the string is a palindrome', () => {
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expect(palindromeCheck('a')).toBe(true);
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expect(palindromeCheck('pop')).toBe(true);
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expect(palindromeCheck('deed')).toBe(true);
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expect(palindromeCheck('kayak')).toBe(true);
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expect(palindromeCheck('racecar')).toBe(true);
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expect(palindromeCheck('rad')).toBe(false);
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expect(palindromeCheck('dodo')).toBe(false);
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expect(palindromeCheck('polo')).toBe(false);
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});
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});
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/**
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* @param {string} string
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* @return {boolean}
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*/
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export default function palindromeCheck(string) {
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let left = 0;
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let right = string.length - 1;
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while (left < right) {
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if (string[left] !== string[right]) {
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return false;
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}
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left += 1;
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right -= 1;
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}
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return true;
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}

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