Parser should report an error when 'super' is used as an expression.

[scheglov]

[Comment by eernstg: Note that the analyzer still does not report an error in the example shown here. I'm changing the labels accordingly.]

This code currently has no errors in analyzer, but fails with CFE.
I think this is a bug in the analyzer.
But as @bwilkerson correctly pointed out, this is a syntactic error, and reported by the parser.

class A {
  int foo() => 0;
}

class B extends A {
  void bar() {
    print(super);
    super!;
  }
}

main() {
  B().bar();
}

[jonasfj]

I'm not entirely sure why I was assigned (typo?) :D

[bwilkerson]

@jensjoha

[sgrekhov]

This is still an issue

class C {
  foo() {
    print(super); // No error in analyzer, in CFE Error: Can't use 'super' as an expression.
  }
}

main() {
  C().foo();
}

Dart SDK version: 2.19.0-81.0.dev (dev) (Tue Aug 9 14:51:36 2022 -0700) on "windows_x64"

@eernstg please confirm that it is an analyzer issue

[eernstg]

I agree that this is still an issue in the analyzer, I changed the labels accordingly.

[bwilkerson]

I agree that this is still an issue in the analyzer, I changed the labels accordingly.

I don't understand why this isn't an issue for the parser. My understanding is that parse(super); is not valid Dart code because it doesn't conform to the grammar. Such problems should be caught by the parser so that we can avoid exactly the kind of inconsistency between the front end and the analyzer that's been mentioned above.

[eernstg]

Oh, it could very well be an issue for the parser, but I just verified that the error is missing for the analyzer, and it is reported for the CFE.

[bwilkerson]

@jensjoha