Prefer #any-of?
predicate over #match?
with alternation
#80
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The
(#match? @foo "^(bar|baz)$")
predicate was a workaround necessary when#any-of?
was not broadly supported. Now that it has been standard for a while, we can switch these uses of#match?
to#any-of?
.https://tree-sitter.github.io/tree-sitter/using-parsers/queries/3-predicates-and-directives.html#the-any-of-predicate