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[WIP] gh-132166: Add check in find_longest_match for checking if sequences are identical #132167

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6 changes: 6 additions & 0 deletions Lib/difflib.py
Original file line number Diff line number Diff line change
Expand Up @@ -365,6 +365,12 @@ def find_longest_match(self, alo=0, ahi=None, blo=0, bhi=None):
ahi = len(a)
if bhi is None:
bhi = len(b)

# Check if both sequences are the same before executing rest of the
# method.
if a[alo:ahi] == b[blo:bhi]:
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Is this covered in tests? if not, please add a test, otherwise no need to add a large one.

return Match(alo, blo, len(a[alo:ahi]))

besti, bestj, bestsize = alo, blo, 0
# find longest junk-free match
# during an iteration of the loop, j2len[j] = length of longest
Expand Down
Original file line number Diff line number Diff line change
@@ -0,0 +1,5 @@
Add checking if sequences ``a[alo:ahi]`` and ``b[blo:bhi]`` are the same on the
beginning of the method find_longest_match in SequenceMatcher. For identical
sequences there is no reason to run whole logic when simple check can be done.
Comment on lines +1 to +3
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This NEWS should be summarized. I suggest something like (assumiong that the method is documented, if not use a plain

Add a fast path in :meth:`SequenceMatcher.find_longest_match
<difflib.SequenceMatcher.find_longest_match>` to handle the
case when ``a[alo:ahi] == b[blo:bhi]``.

It appears to fix issue when comparing two slightly different strings ends up
with waiting forever for the result.
Comment on lines +4 to +5
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Suggested change
It appears to fix issue when comparing two slightly different strings ends up
with waiting forever for the result.
It appears to fix issue when comparing two slightly different strings ends up
with waiting forever for the result.

We should be more confident here. Does it fix the issue or not? if so, let's say it. Otherwise, let's not give tentative conclusions.

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